3[1-2(x-3)]=4(y+3)

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Solution for 3[1-2(x-3)]=4(y+3) equation:


Simplifying
3[1 + -2(x + -3)] = 4(y + 3)

Reorder the terms:
3[1 + -2(-3 + x)] = 4(y + 3)
3[1 + (-3 * -2 + x * -2)] = 4(y + 3)
3[1 + (6 + -2x)] = 4(y + 3)

Combine like terms: 1 + 6 = 7
3[7 + -2x] = 4(y + 3)
[7 * 3 + -2x * 3] = 4(y + 3)
[21 + -6x] = 4(y + 3)

Reorder the terms:
21 + -6x = 4(3 + y)
21 + -6x = (3 * 4 + y * 4)
21 + -6x = (12 + 4y)

Solving
21 + -6x = 12 + 4y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-21' to each side of the equation.
21 + -21 + -6x = 12 + -21 + 4y

Combine like terms: 21 + -21 = 0
0 + -6x = 12 + -21 + 4y
-6x = 12 + -21 + 4y

Combine like terms: 12 + -21 = -9
-6x = -9 + 4y

Divide each side by '-6'.
x = 1.5 + -0.6666666667y

Simplifying
x = 1.5 + -0.6666666667y

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